计算两个经纬度之间的直线距离－C# 版

ITPOW2016/11/3 16:00:29

double lon1 = 113.264399;
double lat1 = 23.154322;
double lon2 = 113.153728;
double lat2 = 23.059122;

var a = lon1 * Math.PI / 180.0 - lon2 * Math.PI / 180.0;
var radLat1 = lat1 * Math.PI / 180.0;;
var radLat2 = lat2 * Math.PI / 180.0;;
var b = radLat1 - radLat2;

var s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(b / 2), 2) +
Math.Cos(radLat1)*Math.Cos(radLat2)*Math.Pow(Math.Sin(a / 2), 2)));
s = s * 6378.137 ; // 地球半径，单位千米
s = Math.Round(s * 10000) / 10000;

MessageBox.Show(s.ToString());

如上代码：经纬度来自百度地图的经纬度，计算出来的结果与百度测距的结果一致。

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